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APU3039M View Datasheet(PDF) - Advanced Power Electronics Corp

Part Name
Description
Manufacturer
APU3039M
A-POWER
Advanced Power Electronics Corp 
APU3039M Datasheet PDF : 22 Pages
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Advanced Power
Electronics Corp.
APU3039
The APU3039’s error amplifier is a differential-input
transconductance amplifier. The output is available for
DC gain control or AC phase compensation.
The E/A can be compensated with or without the use of
local feedback. When operated without local feedback,
the transconductance properties of the E/A become evi-
dent and can be used to cancel one of the output filter
poles. This will be accomplished with a series RC circuit
from Comp pin to ground as shown in Figure 12.
Note that this method requires that the output capacitor
should have enough ESR to satisfy stability requirements.
In general, the output capacitor’s ESR generates a zero
typically at 5KHz to 50KHz which is essential for an
acceptable phase margin.
The ESR zero of the output capacitor expressed as fol-
lows:
FESR
=
2π
x
1
ESR
x
Co
---(14)
VOUT
R6 Fb
R5
Vp=VREF
E/A
Comp
Ve
C9
R4
Gain(dB)
H(s) dB
First select the desired zero-crossover frequency (Fo):
Fo > FESR and FO [ (1/5 ~ 1/10) x fS
Use the following equation to calculate R4:
R4
=
VOSC
VIN
x
FoxFESR
FLC2
x
R5 + R6
R5
x
1
gm
---(18)
Where:
VIN = Maximum Input Voltage
VOSC = Oscillator Ramp Voltage
Fo = Crossover Frequency
FESR = Zero Frequency of the Output Capacitor
FLC = Resonant Frequency of the Output Filter
R5 and R6 = Resistor Dividers for Output Voltage
Programming
gm = Error Amplifier Transconductance
For:
VIN = 18V
VOSC = 1.25V
Fo = 20KHz
FESR = 12KHz
FLC = 2.8KHz
R5 = 1K
R6 = 3.16K
gm = 700µmho
This results to R4=12.08K
Choose R4=14K
To cancel one of the LC filter poles, place the zero be-
fore the LC filter resonant frequency pole:
FZ 75%FLC
FZ 0.75X
2π
For:
Lo = 4.7µH
Co = 660µF
1
LO x CO
---(19)
FZ = 2.1KHz
R4 = 14K
FZ Frequency
Figure 12 - Compensation network without local
feedback and its asymptotic gain plot.
The transfer function (Ve / VOUT) is given by:
( ) H(s) =
gm x
R5
R6 + R5
x
1 + sR4C9
sC9
---(15)
The (s) indicates that the transfer function varies as a
function of frequency. This configuration introduces a gain
and zero, expressed by:
|H(s=jx2πxFO)|
=
gm
x
R5
R6xR5
x
R4
---(16)
FZ
=
1
2πxR4xC9
---(17)
|H(s)| is the gain at zero cross frequency.
Using equations (17) and (19) to calculate C9, we get:
C9 5300pF; Choose C9 =5600pF
One more capacitor is sometimes added in parallel with
C9 and R4. This introduces one more pole which is mainly
used to suppress the switching noise. The additional
pole is given by:
1
FP
=
2
π
x
R
4
x
C9xCPOLE
C9 + CPOLE
The pole sets to one half of switching frequency which
results in the capacitor CPOLE:
CPOLE =
1
π x R4 x fS -
1
C9
for FP <<
fS
2
1
πx R4xfS
11

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