Current Mode PWM Controller
A set of formulas are given to determine the values of RT and CT for a given frequency and maximum duty
cycle. (Note: These formulas are less accurate for smaller duty cycles or higher frequencies. This will require
trimming of RT or CT to correct for this error.)
Example:
A Flyback power supply requires a maximum of 45% duty cycle at a switching frequency of 50 kHz. What
are the values of RT and CT?
Given:
f = 50kHz
Dm = 0.45
1
Calculate: RT = 267 �(1.76)..4555 − 1� = 674 Ω
(1.76).45− 1
1.86 ∗ 0.45
CT = 50000 ∗ 674 = .025 (µF)
1000
100
10
R
T
RT
=
=
680Ω
2kΩ
RT = 5kΩ
R
T
=
10kΩ
RRRRRTTTTT=====3257100000kkkk0ΩΩΩΩkΩ
1
.001
.002
.005
.01
.05
0.1
CT Value - (µF)
Figure 16 · Oscillator Frequency Vs. RT For Various CT
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