TB62731FUG
Substitute the following conditions in formula 2.
Supply voltage VIN = 3.0~4.3 (V)
Output-side capacitor C2 = 1 (µF) . . . C2 is ignored in the calculation.
Where it is assumed that,
VfLED = 16 (V), Vf schottky = 0.3 (V), R_sens = 1.8 (Ω), Io = 20 (mA), K = 1.1
VfLED: LED Vf
Vf schottky: schottky diode Vf
R_sens: setting resistance
Io: set current
K: margin
L (µH) = ((1.1 × 16 × 0.02) − 3 × 0.02) × (1/275e3) × 2 × (1/(0.21 × 0.21)) = 48.1 (µH, VIN = 3.0 V)
43.8 (µH, VIN = 4.3 V)
Thus, 48.1 (µH) is selected when the input voltage is low, 3.0 V.
Note that the calculation does not consider fluctuations in inductance. Toshiba recommend selection of an
inductance of 1.2 times the calculated value.
The recommended inductance under the above conditions is L (µH) = 48.1 (µH) × 1.2 >= 57.7 (µH).
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2004-09-14