LT1939
APPLICATIONS INFORMATION
The following example along with the data in Table 1
illustrates the tradeoffs of switch frequency selection.
Example.
VIN = 25V, VOUT1 = 3.3V, IOUT1 = 2A,
Temperature = 0°C to 85°C
tON(MIN) = 185ns (85°C from Typical Characteris-
tics
graph), VD = 0.6V, VSW = 0.4V (85°C)
Max
Frequency =
3.3 + 0.6
25 0.4 + 0.6
•
1
185ns
~ 835kHz
RT/SYNC ~ 49.9k
Frequency ≅ 820kHz
Input Voltage Range
Once the switching frequency has been determined, the
input voltage range of the regulator can be determined.
The minimum input voltage is determined by either the
LT1939’s minimum operating voltage of ~2.8V or by its
maximum duty cycle. The duty cycle is the fraction of time
that the internal switch is on during a clock cycle. The
maximum duty cycle can be determined from the clock
frequency and the minimum off time from the typical
characteristics graph.
This leads to a minimum input voltage of:
VIN(MIN)
=
VOUT1 + VD
DCMAX
VD
+
VSW
where VSW is the voltage drop of the internal switch,
and
DCMAX = 1 – tOFF(MIN) • Frequency.
Figure 3 shows a typical graph of minimum input voltage
vs load current for 3.3V and 5V applications.
The maximum input voltage is determined by the absolute
maximum ratings of the VIN and BST pins and by the
frequency and minimum duty cycle.
The minimum duty cycle is defined as:
DCMIN = tON(MIN) • Frequency
Maximum input voltage as:
VIN(MAX)
=
VOUT1 + VD
DCMIN
VD
+
VSW
8
FSW = 1MHz
L = 3.3μH
7
6
5
4
VOUT1 = 5V START-UP
3
VOUT1 = 5V RUNNING
VOUT1 = 3.3V START-UP
VOUT1 = 3.3V RUNNING
2
0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1.6 1.8 2.0
LOAD CURRENT (A)
1939 F03
Figure 3. Minimum Input Voltage vs Load Current
Table 1. Efficiency and Size Comparisons for Different RRT/SYNC Values, 3.3V Output
FREQUENCY
RT/SYNC
EFFICIENCY
VIN(MAX)
L
2.5MHz
15k
73.6
12
1μ
2.0MHz
20k
81.5
14
1.5μ
1.5MHz
24.9k
84.5
18
2.2μ
1.0MHz
40.2k
87.3
25
3.3μ
500kHz
90.9k
88.9
25
4.7μ
C
C + L AREA
(mm2)
10μ
24
10μ
24
10μ
24
22μ
34
47μ
40
1939f
11