LTC6102
LTC6102-1/LTC6102HV
Applications Information
a significant load on the power supply and create thermal
design headaches. In addition, heating in the sense resistor
can reduce its accuracy and reliability.
In contrast, the large dynamic range of the LTC6102 allows
the use of a much smaller sense resistor. The LTC6102
allows the minimum sense voltage to be reduced to less
than 10µV. The peak sense voltage would then be 10mV,
dissipating only 1W at 100A in a 100µΩ sense resistor!
With a specialized sense resistor, the same system would
allow peak currents of more than 1000A without exceeding
the input range of the LTC6102 or damaging the shunt.
high-current paths, this error can be reduced by orders of
magnitude. A sense resistor with integrated Kelvin sense
terminals will give the best results. Figure 2 illustrates the
recommended method. Note that the LTC6102 has a Kelvin
input structure such that current flows into –INF. The –INS
and –INF pins should be tied as close as possible to RIN.
This reduces the parasitic series resistance so that RIN
may be as low as 1Ω, allowing high gain settings to be
used with very little gain error.
V+
TIE AS CLOSE TO RIN AS POSSIBLE
Dynamic Range vs Maximum
Power Dissipation in RSENSE
110
RSENSE = 100mΩ RSENSE = 10mΩ
100
RSENSE = 1Ω
90
80
100dB: MAX
VSENSE = 1V
70
60
40dB: MAX
VSENSE = 1mV
50
40
RSENSE = 10µΩ
RSENSE = 100µΩ
30
RSENSE = 1mΩ
20
0.001 0.01 0.1
1
10
100
MAXIMUM POWER DISSIPATION (W)
DYNAMIC RANGE RELATIVE
TO 10µV, MINIMUM VSENSE
MAX ISENSE = 1A
MAX ISENSE = 10A
MAX ISENSE = 100A
6102 AI01
Sense Resistor Connection
Kelvin connection of +IN and –INS to the sense resistor
should be used in all but the lowest power applications.
Solder connections and PC board interconnections that
carry high current can cause significant error in measure-
ment due to their relatively large resistances. One 10mm
× 10mm square trace of one-ounce copper is approxi-
mately 0.5mΩ. A 1mV error can be caused by as little
as 2A flowing through this small interconnect. This will
cause a 1% error in a 100mV signal. A 10A load current
in the same interconnect will cause a 5% error for the
same 100mV signal. An additional error is caused by the
change in copper resistance over temperature, which is in
excess of 0.4%/°C. By isolating the sense traces from the
RSENSE
RIN–
RIN+ +IN
LOAD
V–
+–
LTC6102
–INS
–INF
V+
VREG
0.1µF
OUT
VOUT
ROUT
RSENSE*
V+
LOAD
RIN–
RIN+
OUTPUT
ROUT
V–
LTC6102
CREG
V–
*VISHAY VCS1625 SERIES
WITH 4 PAD KELVIN CONNECTION
6102 F02
Figure 2. Kelvin Input Connection Preserves Accuracy
with Large Load Current and Large Output Current
Selection of External Input Resistor, RIN
The external input resistor, RIN, controls the transconduc-
tance of the current sense circuit, IOUT = VSENSE/RIN. For
example, if RIN = 100, then IOUT = VSENSE/100 or IOUT =
1mA for VSENSE = 100mV.
RIN should be chosen to provide the required resolution
while limiting the output current. At low supply voltage,
IOUT may be as much as 1mA. By setting RIN such that
For more information www.linear.com/LTC6102
6102fe
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