TS4962M(2005) View Datasheet(PDF) - STMicroelectronics

Part Name

Description

Manufacturer

TS4962M
(Rev.:2005)

3W Filter-free Class D Audio Power Amplifier

STMicroelectronics 

Application Information

TS4962M

5.3

Common mode feedback loop limitations

As explained previously, the common mode feedback loop allows the output DC bias voltage to

be averaged at VCC/2 for any DC common mode bias input voltage.

However, due to Vicm limitation in the input stage (see Table 2: Operating conditions on page 2),

the common mode feedback loop can ensure its role only within a defined range. This range

depends upon the values of VCC and Rin (Av). To have a good estimation of the Vicm value, we

can apply this formula (no tolerance on Rin):

Vicm

=

V-----C---C-----×-----R-----i-n----+-----2-----×-----V----I--C----×-----1----5---0----k---Ω---

2 × (Rin + 150kΩ)

(V)

with

VIC

=

I---n---+----+-----I--n-----

2

(V)

and the result of the calculation must be in the range:

0.5V ≤ Vicm ≤ VCC – 0.8V

Due to the +/-9% tolerance on the 150kΩ resistor, it’s also important to check Vicm in these

conditions:

V-----C---C-----×--2---R--×---i-n(---R-+---i--n2----+-×----1-V--3--I-6-C---.-5×----k-1--Ω--3---6)---.--5----k---Ω--- ≤ Vicm ≤ V-----C---C-----×--2---R-×----i-n(---R-+---i--n2----+-×----1-V--6--I-3-C---.-5×----k-1--Ω--6---3)---.--5----k---Ω---

If the result of Vicm calculation is not in the previous range, input coupling capacitors must be

used (with VCC from 2.4V to 2.5V, input coupling capacitors are mandatory).

For example:

With VCC = 3V, Rin = 150k and VIC = 2.5V, we found Vicm = 2V typically and this is lower than

3V - 0.8V = 2.2V. With 136.5kΩ we found 1.97V and with 163.5kΩ we have 2.02V. So, no input

coupling capacitors are required.

5.4 Low frequency response

If a low frequency bandwidth limitation is requested, it’s possible to use input coupling

capacitors.

In the low frequency region, Cin (input coupling capacitor) starts to have an effect. Cin forms,

with Rin, a first order high-pass filter with a -3dB cut-off frequency:

FCL

=

-----------------1-------------------

2π × Rin × Cin

(Hz)

So, for a desired cut-off frequency we can calculate Cin,

Cin = -2---π-----×-----R----1i--n----×-----F----C---L-

(F)

with Rin in W and FCL in Hz.

22/32

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