NXP Semiconductors
TEA1610P; TEA1610T
Zero-voltage-switching resonant converter controller
8.4 Minimum frequency resistor
The Rf(min) resistor is connected between the VREF pin (3 V reference voltage) and the IRS
current input (held at a temperature independent voltage level of 0.6 V). The charge
current of the capacitor Cf is twice the current flowing into the IRS pin.
The Rf(min) resistor has a voltage drop of 2.4 V and its resistance defines the minimum
charge current (rising slope) of the Cf capacitor if the control current is zero. The minimum
frequency is defined by this minimum charge current (IIRS1) and the discharge current:
IIRS1
=
----2---.-4---V------
R f (min)
tIRS1 = -C--2---f--×-×---I--∆-I--R-V--S--C-1---f
f osc(min)
=
-----------1------------
tdt + tIRS1
f bridge(min) = -f---o---s--c-2-(--m----i-n---)
8.5 Maximum frequency resistor
The output voltage is regulated by changing the frequency of the half-bridge converter.
The maximum frequency is determined by the R∆f resistor which is connected between
the error amplifier output VCO and the oscillator current input pin IRS. The current that
flows through the R∆f resistor (IIRS2) is added to the current flowing through the Rf(min)
resistor. As a result, the charge current ICF increases and the oscillation frequency
increases. As the falling slope of the oscillator is constant, the relationship between the
output frequency and the charge current is not a linear function (see Figure 7 and
Figure 9):
I IRS2 = V-----V---C--R-O---∆--–-f----0---.-6-
tIRS2 = 2-----×-----C(--I---fI--R-×--S--1-∆---+-V----IC---I-fR----S--2---)
The maximum output voltage of the error amplifier and the value of R∆f determine the
maximum frequency:
I IRS2(max) = V-----V---C---O----(-R-m---∆a---xf--)---–-----0---.-6--
tIRS(min) = 2-----×-----(--I---I-C-R---S-f-2--×--+---∆--I--V-I--R--C-S--f2---(--m---a---x--)---)
f osc(max) = T-----O-1--S---C-
TEA1610T_P_3
Product data sheet
Rev. 03 — 26 March 2007
© NXP B.V. 2007. All rights reserved.
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