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A8514KLPTR-T 查看數據表(PDF) - Allegro MicroSystems

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A8514KLPTR-T Datasheet PDF : 35 Pages
First Prev 31 32 33 34 35
A8514
Wide Input Voltage Range, High Efficiency
Fault Tolerant LED Driver
tions, due to stringent EMI requirements, the system must operate
in continuous conduction mode throughout the whole input volt-
age range.
Step 4a Determining the duty cycle, calculated as follows:
D(max) =
VOUT(OVP) + Vd
VIN(min) + VOUT(OVP) + Vd
(35)
= 15.9 (V) + 0.4 (V)
= 76.5%
5 (V) + 15.9 (V) + 0.4 (V)
Step 4b Determining the maximum and minimum input current
to the system. The minimum input current will dictate the induc-
tor value. The maximum current rating will dictate the current
rating of the inductor. First, the maximum input current, given:
IOUT = #CHANNELS ILED
(36)
= 4 0.060 (A) = 0.240 A
then:
IIN(max) =
VOUT(OVP)
VIN(min)
IOUT
H
(37)
= 15.9 (V) 0.24 (A) = 0.848 A
5 (V) 0.90
then:
L = VIN(min) D(max)
(40)
ΔIL fSW
=
5 (V)
0.765 = 7.53 μH
0.254 (A) 2 (MHz)
Step 4d Double-check to make sure the ½ current ripple is less
than IIN(min):
IIN(min) > 1/2 ΔIL
(41)
0.265 A > 0.127 A
A good inductor value to use would be 10 μH.
Step 4e Next insert the inductor value used in the design to deter-
mine the actual inductor ripple current:
ΔILused =
VIN(min)
Lused
D(max)
fSW
(42)
= 5 (V) 0.765 = 0.191 A
10 (μH) 2.0 (MHz)
where η is efficiency.
Next, calculate minimum input current, as follows:
IIN(min) =
VOUT(OVP)
VIN(max)
IOUT
H
(38)
= 15.9 (V) 0.24 (A) = 0.265 A
16 (V) 0.90
Step 4c Determining the inductor value. To ensure that the induc-
tor operates in continuous conduction mode, the value of the
inductor must be set such that the ½ inductor ripple current is not
greater than the average minimum input current. As a first pass
assume Iripple to be 30% of the maximum inductor current:
ΔIL = IIN(max) × Iripple
(39)
= 0.848 × 0.30 = 0.254 A
Step 4f Determining the inductor current rating. The inductor
current rating must be greater than the IIN(max) value plus half of
the ripple current ΔIL, calculated as follows:
L(min) = IIN(max) + 1/2 ΔILused
(43)
= 0.848 (A) + 0.096 (A) = 0.944 A
Step 5 Determining the resistor value for a particular switching
frequency. Use the RFSET values shown in figure 7. For example,
a 10 kΩ resistor will result in a 2 MHz switching frequency.
Step 6 Choosing the proper switching diode. The switching diode
must be chosen for three characteristics when it is used in LED
lighting circuitry. The most obvious two are: current rating of the
diode and reverse voltage rating.
Allegro MicroSystems, Inc.
31
115 Northeast Cutoff
Worcester, Massachusetts 01615-0036 U.S.A.
1.508.853.5000; www.allegromicro.com

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