NCP1028
The principle consists in selecting the RR resistor,
connected from pin 2 to ground, to impose a current IRR in
the transistor collector.
Figure 38. Maximum Peak Current Setpoint
Variations versus Ramp Compensation
The equation to get the right compensation level is the
following:
RR
+
Vp2.75 k
Sa@TSW
(eq. 9)
where Vp, the total voltage swing, equals 2.75 V.
Application example:
Suppose we have the following flyback specifications:
Vout = 5.0 V
output voltage
Vf = 1.0 V
secondary diode forward drop
@ Iout nominal
Np:Ns = 1:N = 1:0.052 transformer turn ratio
Lp = 3.8 mH
primary inductance
We can calculate the off slope, the one actually needed
to evaluate Sa, by reflecting the output voltage over the
primary inductance. The slope is projected over a complete
switching period. Here, we use a 65 kHz part.
Soff +
Vout ) Vf
NLp
TSW
+
6
0.052
15u
3.8m
+
455
mAń15
ms
(eq. 10)
Due to the internal sense arrangement, this current slope
will become a voltage slope having a value of:
SȀoff + 455m 0.375 + 170 mVń15 ms (eq. 11)
If we chose 50% of this downslope, then the final
compensation ramp will present a slope of:
Sa
+
170m
2
+
85
mVń15
ms
(eq. 12)
We then have:
RR
+
Vp2.75 k
Sa@TSW
+
2.75 2.75k
85m
+
89
kW
(eq. 13)
In the above calculations, the internal ESD resistor has
purposely been omitted to avoid bringing in another
variable. In case no ramp compensation is required, pin 2
must be tied to VCC, the adjacent pin.
Soft−Start
The NCP1028 features a 1.0 ms soft−start, which
reduces the power−on stress, but also contributes to lower
the output overshoot. Figure 39 shows a typical operating
waveform. The NCP1028 features a novel patented
structure which offers a better soft−start ramp, almost
ignoring the startup pedestal inherent to traditional
current−mode supplies.
Figure 39. 1.0 ms Soft−Start Sequence
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